Edexcel Pure Paper 1 2024 Question 12
Edexcel Pure Paper 1 2024 Question 12 β Trigonometric Modelling and Interpretation
β The Question
π§ Before you start
This one looks long, but itβs really just the same idea repeated.
Everything comes from rewriting:
140\cos\theta – 480\sin\theta
into a single cosine form.
Once thatβs done, the rest is just using it carefully.
Where people struggled wasnβt the maths β it was:
- mixing degrees and radians
- not using earlier parts properly
or losing track of what the model actually means
βοΈ Working
Part (a)
We want:
140\cos\theta – 480\sin\theta = K\cos(\theta + \alpha)
Compare coefficients:
K\cos\alpha = 140
K\sin\alpha = 480
Find K:
K = \sqrt{140^2 + 480^2}
= \sqrt{19600 + 230400}
= \sqrt{250000} = 500
Now find \alpha:
\tan\alpha = \frac{480}{140}
\alpha \approx 73.74^\circ
So:
140\cos\theta – 480\sin\theta = 500\cos(\theta + 73.74^\circ)
Part (b)(i)
Model is:
R = A + 140\cos(30t) – 480\sin(30t)
Use part (a):
R = A + 500\cos(30t + 73.74^\circ)
We are told the maximum value is 1500.
Max of cosine = 1, so:
A + 500 = 1500
A = 1000
So the model becomes:
R = 1000 + 500\cos(30t + 73.74^\circ)
Part (b)(ii)
Minimum occurs when cosine = -1:
R_{\min} = 1000 – 500 = 500
Part (c)
Minimum is said to happen in middle of April.
That corresponds to:
t = 3.5
Substitute:
R = 1000 + 500\cos(30(3.5) + 73.74)
= 1000 + 500\cos(178.74^\circ)
This is approximately:
R \approx 500
So the model predicts the minimum at about the right time.
Conclusion:
The model is reasonable / reliable.
Part (d)
We are told foxes are minimum.
So:
\sin(30t + 70) = -1
That happens at:
30t + 70 = 270
30t = 200
t = \frac{20}{3}
Now substitute into rabbit model:
R = 1000 + 500\cos(30 \cdot \frac{20}{3} + 73.74)
= 1000 + 500\cos(200 + 73.74)
= 1000 + 500\cos(273.74^\circ)
\approx 1032
β Final Answer
1032 \text{ (or } 1033\text{)}
π― Where the Marks Are
Part (a):
- B1 correct K
- M1 correct trig setup
- A1 correct angle
Part (b):
- B1 correct model
- B1 correct minimum
Part (c):
- M1 correct substitution
- A1 valid interpretation
Part (d):
- M1 solving trig equation
- A1 correct t
- M1 substitution
- A1 final answer
β οΈ What Went Wrong
A lot of issues here were quite small, but they added up.
In part (a), some used radians instead of degrees. That immediately gives the wrong angle. Others reversed the tangent fraction and used \frac{140}{480} instead.
Part (b) caused more problems than expected.
Many didnβt use the result from part (a), even though it made things much easier. Instead, they tried to work directly with sine and cosine, which made it harder to identify the maximum.
In part (c), interpretation was the issue.
Some used values like t = 4 or t = 4.5, rather than recognising βmiddle of Aprilβ as about 3.5 months.
That small detail made a difference.
Part (d) was generally done well, but mistakes still appeared.
Some solved:
\sin(…) = 1
instead of -1.
Others used angles like 90Β° or 180Β°, which donβt give the minimum.
A few ended up with negative time values, which should have been a clear sign something had gone wrong.
π‘ The takeaway
This question is about consistency.
Once you get the harmonic form, everything else follows from it.
But you need to:
- stay in degrees
- use earlier results
and interpret carefully
π If This Felt Difficult
If this felt a bit scattered, thatβs normal.
This type of modelling question mixes algebra, trig and interpretation.
Working through more of these in a maths revision support course helps bring those ideas together.
And if you want more targeted help with A level maths, especially on trig modelling, regular practice makes a big difference.
π Next Steps
- β Question 11
- β Question 13
π¨βπ«Author Bio
S. Mahandru is an experienced A Level Maths teacher and founder of Exam.Tips, specialising in exam-focused revision techniques and helping students achieve top grades.
β Frequently Asked Questions
π Why use harmonic form?
It makes maximum and minimum values much easier to identify.
π Why degrees, not radians?
The question is set in degrees β using radians gives wrong answers.
π How do I find minimum value?
Use cosine = -1 once in harmonic form.
π Whatβs the main mistake here?
Not using part (a) properly in later parts.