The total power input to a pumped storage power station is 600 MW

The total power input to a pumped storage power station is 600 MW. The useful power output is 540 MW. Calculate the efficiency of this pumped storage power station.

1. In order to determine the efficiency of the pumped storage power station, we need to first understand the concept of efficiency in this context. Efficiency is a measure of how well a system converts input energy into useful output energy. In this case, the total power input to the station is given as 600 MW, while the useful power output is 540 MW. The efficiency of the pumped storage power station can be calculated by dividing the useful power output by the total power input and then multiplying by 100 to express the result as a percentage.

2. By applying the formula for efficiency, we can calculate the efficiency of the pumped storage power station as follows: Efficiency = (Useful power output / Total power input) x 100. Substituting the given values into the formula, we get: Efficiency = (540 MW / 600 MW) x 100 = 0.9 x 100 = 90%. Therefore, the efficiency of this pumped storage power station is 90%. This means that 90% of the total power input is converted into useful power output, while the remaining 10% is lost as heat or other forms of energy.

3. Understanding the efficiency of a power station is crucial for assessing its performance and effectiveness in converting energy. In the case of the pumped storage power station with a total power input of 600 MW and a useful power output of 540 MW, the efficiency of 90% indicates that the station is operating at a high level of efficiency. This means that the station is able to convert a large portion of the input energy into useful output energy, making it an efficient and effective system for generating power.

Boost your learning with an online physics tutor.